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Κώδικας: Επιλογή όλων

/* LANG: C++
 * TASK: Alexander
 */

#include <stdio.h>
#include <stdlib.h>

int main()
{
	int L=0, C=0, i, j; /* L=lines C=chars per line*/
	char prevc='\0', plinec;
	FILE *fp;


	fp=fopen("Alexander.in", "r");
	fscanf(fp, "%d %d %c", &L, &C, &prevc);
	fclose(fp);

	
	if(prevc=='P') prevc = 'V';
	else prevc = 'P';
	plinec = prevc;
	

	fp=fopen("Alexander.out", "w");
	for(j=0; j<L; j++)/*for every line*/
	{
		prevc = plinec; /*the previous character is count as the beginning of the previous line.*/
		if(prevc == 'P')
		{	
			plinec = 'V';
			for(i=0; i<C; i=i+2) fprintf(fp, "VP");
		}
		else
		{
			plinec = 'P';
			for(i=0; i<C; i=i+2) fprintf(fp, "PV");
		}
		if(C-i > 0)
		{
			if(prevc=='P') fprintf(fp, "V");
			else fprintf(fp, "P");
		}

		fprintf(fp, "\n");		
	}
	fclose(fp);
	
	return(0);
}

Κώδικας: Επιλογή όλων

/*
LANG: C
TASK: Alexander
*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char *argv[])
{
    FILE *in, *out;
    int i=0, lines, cols, sw, loopy;
    char *pv, *vp, first;
    
    in = fopen("Alexander.in","r");
    fscanf(in,"%d %d\n%c",&lines,&cols,&first);
    if((lines%2) != 0)
    {
          loopy = (lines/2) + 1;
    }else{
          loopy = (lines/2);
    }
    fclose(in);
    pv = (char *) malloc ((cols+1)*sizeof(char));
    vp = (char *) malloc ((cols+1)*sizeof(char));
    sw = 0;
    for(i=0;i<cols;i++)
    {
                           if((sw%2) == 0)
                           {
                           strcat(pv,"P");
                           strcat(vp,"V");
                           sw++;
                           }
                           else
                           {
                               strcat(pv,"V");
                               strcat(vp,"P");
                               sw++;
                               }
    }
    if(first == 'P')//Switch initialisation
    {
                sw = 0;
    }else{
                sw = 1;
    }
    out = fopen("Alexander.out","w");//GRafw twra
    for(i=0;i<loopy;i++)
    {
                if(sw == 0)
                {
                      fputs(pv,out);
                      fprintf(out,"\n");
                      if(i != (loopy-1))
                      {
                           fputs(vp,out);
                           fprintf(out,"\n");
                      }else if(i == (loopy-1) && (lines%2) == 0)
                      {
                            fputs(vp,out);
                            fprintf(out,"\n");
                      }
                }else{
                      fputs(vp,out);
                      fprintf(out,"\n");
                      if(i != (loopy-1))
                      {
                           fputs(pv,out);
                           fprintf(out,"\n");
                      }else if(i == (loopy-1) && (lines%2) == 0)
                      {
                            fputs(pv,out);
                            fprintf(out,"\n");
                      }
                      
                }
    }
    fclose(out);
    return(0);
                                
                
}

Κώδικας: Επιλογή όλων

/*
LANG: C++
TASK: Alexander
*/
#include <iostream>
#include <fstream>
#include <math.h>
#include <stdlib.h>
#include <string>

using namespace std;


int main() {

  int x,y,k;
  char firstc;
  ifstream file_in;
  ofstream file_out;
  file_in.open ("Alexander.in");
  file_in >> x;
  file_in >> y;
  file_in >> firstc;
  
  if(firstc=='P') {
    k=0;
  }
  if(firstc=='V') {
    k=1;
  }
  
  file_in.close();
  file_out.open ("Alexander.out");
  
  for(int a=0;a<x;a++) {
    for(int b=0;b<y;b++) {
      if(k%2==0) {
        file_out <<"P"; 
      }
      if(k%2==1) {
        file_out <<"V";
      }
      k++;
    }
    file_out << "\n";
    if(y%2==0) {
      k++;
    }
    if(y%2==1) {
      k=k;
    } 
    
  }
  file_out.close();
  return(0);
}